Flux and Gauss Law

Introduction, Today we learned about Gauss Law. We learned that flux = E.A or flux is equal to the closed surface integral of the electric field dotted with dA (the areas that makes up the entire surface)

or the charge enclosed over some constant epsilon not(q/epsilon). 

Note net electric force is always the same anywhere in the field defined so we can relate F=qE=ma

Here we have two charges to which we find the electric dipole moment, which is similar to moment of inertia. So what we did was let F= qEsin(theta) and then say r= d/2. so torque is F(d/2) + F(d/2), or qEdsin(theta) or pxE. potential energy is qrE. (think m=q, h=r, E=g)

In conclusion the Flux is dependent on the surface area or area perpindicular to field and the strength of the field or E.A. The electric dipole moment can be said to equal pxF.