Wednesday, September 3, 2014

Gas Laws and First Law


When the hot can with steam inside made contact with the room temperature water it rapidly imploded, due to the low pressure in the can relative to the pressure outside.
We experimented with a balloon and a marshmallow as to what would happen if we decreased the pressure inside the the vacuum chamber, then let back to normal.

What hypothesized above was wrong,what happened was the marshmallow much like the balloon increased in size when the pressure decreased then rapidly shrunk to a size smaller than before when the pressure was normalized.

Here is a makeshift manometer. a manometer is an instrument that uses a liquid to measure pressure!

So each side has a pressure one is known as the applied pressure and the other is our atmospheric pressure. To find the hydro static we  use P=ρhg, however if we just want the pressure applied we can just subtract the reference pressure (atmospheric) pressure. We found that our applied pressure was 101026 Pa and that the mass or amount of water displaced was 5.3 * 10^-5
Here is how we think pressure and volume correspond! (which is wrong)

Here we saw Andrew pumping air into a pressure sensor!
We took measurements of the pressure sensor when at different volumes, every cubic centimeter  (cc)  you can see how the relationship of Pressure vs Volume is not linear but in fact are best described as inversely proportional.

Pressure Vs Temperature
This beautiful graph depicting the linear relationship between Temperature and Pressure.
If Volume is held constant you will see a linear relationship
Volume vs Temperature

Here we can see that as temperature increases the volume increases, which means they are linear.
The pressure of the air remains constant because, of the fact that Temperature and Volume are linear and as long as P=nRT/V, and volume and temperature can keep increasing pressure wont change.

As a balloon rises the gas expands! 
Here we solve for mass by multiplying molar mass by the number of moles in the hot air balloon(n=PV/RT)
now we can find the volume if no helium was lost during assent by setting pv/t=PV/T=nR since the number of moles is assumed to be constant and R is a constant.












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